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Grade 12th passMagical Mathematics[Interesting Approach]

How to solve this problem...this is very interesting and useful to us

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Profile image of Saurav Kumar Sagar
9 Years agoGrade 12th pass
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2 Answers

Profile image of Davendar Singh
9 Years ago
 
We can write 99^n=(11^9)n
therefore 11^n=(11^9)n
11^n=11^9n
n=9n
n=0
This would also satisfy the equation
3^n=11^n=99^n
Profile image of Davendar Singh
9 Years ago
sorry for the wrong answer actually we can write 99^n=(3^2n)*(11^n)
which gives us the answer by solving it as n=0